Base | Representation |
---|---|
bin | 1011110110100101100001… |
… | …0010011011111100110011 |
3 | 1201010212221012101221022112 |
4 | 2331221120102123330303 |
5 | 3202010334433113042 |
6 | 43415001334155535 |
7 | 2513363214161324 |
oct | 275513022337463 |
9 | 51125835357275 |
10 | 13032412004147 |
11 | 4175018905188 |
12 | 15659284b2bab |
13 | 736c4997ccb3 |
14 | 330ab493644b |
15 | 179009e08982 |
hex | bda5849bf33 |
13032412004147 has 2 divisors, whose sum is σ = 13032412004148. Its totient is φ = 13032412004146.
The previous prime is 13032412004077. The next prime is 13032412004191. The reversal of 13032412004147 is 74140021423031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13032412004147 - 222 = 13032407809843 is a prime.
It is not a weakly prime, because it can be changed into another prime (13032412004197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516206002073 + 6516206002074.
It is an arithmetic number, because the mean of its divisors is an integer number (6516206002074).
Almost surely, 213032412004147 is an apocalyptic number.
13032412004147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13032412004147 is an equidigital number, since it uses as much as digits as its factorization.
13032412004147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 13032412004147 its reverse (74140021423031), we get a palindrome (87172433427178).
The spelling of 13032412004147 in words is "thirteen trillion, thirty-two billion, four hundred twelve million, four thousand, one hundred forty-seven".
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