1303242523441 has 2 divisors, whose sum is σ = 1303242523442. Its totient is φ = 1303242523440.

The previous prime is 1303242523417. The next prime is 1303242523523. The reversal of 1303242523441 is 1443252423031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1249485782416 + 53756741025 = 1117804^2 + 231855^2 .

It is a cyclic number.

It is not a de Polignac number, because 1303242523441 - 2⁷ = 1303242523313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1303242523397 and 1303242523406.

It is not a weakly prime, because it can be changed into another prime (1303242520441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651621261720 + 651621261721.

It is an arithmetic number, because the mean of its divisors is an integer number (651621261721).

Almost surely, 2^{1303242523441} is an apocalyptic number.

It is an amenable number.

1303242523441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303242523441 is an equidigital number, since it uses as much as digits as its factorization.

1303242523441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 34.

Adding to 1303242523441 its reverse (1443252423031), we get a palindrome (2746494946472).

The spelling of 1303242523441 in words is "one trillion, three hundred three billion, two hundred forty-two million, five hundred twenty-three thousand, four hundred forty-one".