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13032444041 is a prime number
BaseRepresentation
bin11000010001100101…
…10101000010001001
31020122020211202022122
430020302311002021
5203142301202131
65553110301025
7640645642451
oct141062650211
936566752278
1013032444041
115588525111
122638657775
1312c9021266
148b8bb2d61
1551420ed7b
hex308cb5089

13032444041 has 2 divisors, whose sum is σ = 13032444042. Its totient is φ = 13032444040.

The previous prime is 13032444017. The next prime is 13032444059. The reversal of 13032444041 is 14044423031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11821125625 + 1211318416 = 108725^2 + 34804^2 .

It is an emirp because it is prime and its reverse (14044423031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13032444041 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13032444041.

It is not a weakly prime, because it can be changed into another prime (13032444011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516222020 + 6516222021.

It is an arithmetic number, because the mean of its divisors is an integer number (6516222021).

Almost surely, 213032444041 is an apocalyptic number.

It is an amenable number.

13032444041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13032444041 is an equidigital number, since it uses as much as digits as its factorization.

13032444041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 13032444041 its reverse (14044423031), we get a palindrome (27076867072).

The spelling of 13032444041 in words is "thirteen billion, thirty-two million, four hundred forty-four thousand, forty-one".