Base | Representation |
---|---|
bin | 10010111101101111011… |
… | …011000011110111111111 |
3 | 11121120220100100212100211 |
4 | 102331233123003313333 |
5 | 132323021040033143 |
6 | 2434411403333251 |
7 | 163104420044161 |
oct | 22755733036777 |
9 | 4546810325324 |
10 | 1303244455423 |
11 | 462780579609 |
12 | 1906b1b21227 |
13 | 95b8432c751 |
14 | 47112426931 |
15 | 23d78ba549d |
hex | 12f6f6c3dff |
1303244455423 has 2 divisors, whose sum is σ = 1303244455424. Its totient is φ = 1303244455422.
The previous prime is 1303244455411. The next prime is 1303244455427. The reversal of 1303244455423 is 3245544423031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1303244455423 is a prime.
It is a super-2 number, since 2×13032444554232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1303244455427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651622227711 + 651622227712.
It is an arithmetic number, because the mean of its divisors is an integer number (651622227712).
Almost surely, 21303244455423 is an apocalyptic number.
1303244455423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303244455423 is an equidigital number, since it uses as much as digits as its factorization.
1303244455423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 1303244455423 its reverse (3245544423031), we get a palindrome (4548788878454).
The spelling of 1303244455423 in words is "one trillion, three hundred three billion, two hundred forty-four million, four hundred fifty-five thousand, four hundred twenty-three".
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