1303250450053 has 2 divisors, whose sum is σ = 1303250450054. Its totient is φ = 1303250450052.

The previous prime is 1303250450017. The next prime is 1303250450059. The reversal of 1303250450053 is 3500540523031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1165637644609 + 137612805444 = 1079647^2 + 370962^2 .

It is an emirp because it is prime and its reverse (3500540523031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1303250450053 - 2³³ = 1294660515461 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1303250449997 and 1303250450024.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1303250450059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651625225026 + 651625225027.

It is an arithmetic number, because the mean of its divisors is an integer number (651625225027).

Almost surely, 2^{1303250450053} is an apocalyptic number.

It is an amenable number.

1303250450053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303250450053 is an equidigital number, since it uses as much as digits as its factorization.

1303250450053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27000, while the sum is 31.

Adding to 1303250450053 its reverse (3500540523031), we get a palindrome (4803790973084).

The spelling of 1303250450053 in words is "one trillion, three hundred three billion, two hundred fifty million, four hundred fifty thousand, fifty-three".