Base | Representation |
---|---|
bin | 10010111101101111111… |
… | …011110010010000111101 |
3 | 11121120220221111201000120 |
4 | 102331233323302100331 |
5 | 132323030234042140 |
6 | 2434412311245153 |
7 | 163104553003554 |
oct | 22755773622075 |
9 | 4546827451016 |
10 | 1303253034045 |
11 | 4627853a8886 |
12 | 1906b49797b9 |
13 | 95b86044361 |
14 | 4711361ad9b |
15 | 23d797ec1d0 |
hex | 12f6fef243d |
1303253034045 has 16 divisors (see below), whose sum is σ = 2099014161792. Its totient is φ = 690465182400.
The previous prime is 1303253033987. The next prime is 1303253034079. The reversal of 1303253034045 is 5404303523031.
It is not a de Polignac number, because 1303253034045 - 210 = 1303253033021 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1303253033997 and 1303253034015.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 287691562 + ... + 287696091.
It is an arithmetic number, because the mean of its divisors is an integer number (131188385112).
Almost surely, 21303253034045 is an apocalyptic number.
1303253034045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1303253034045 is a deficient number, since it is larger than the sum of its proper divisors (795761127747).
1303253034045 is a wasteful number, since it uses less digits than its factorization.
1303253034045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 575387812.
The product of its (nonzero) digits is 64800, while the sum is 33.
Adding to 1303253034045 its reverse (5404303523031), we get a palindrome (6707556557076).
The spelling of 1303253034045 in words is "one trillion, three hundred three billion, two hundred fifty-three million, thirty-four thousand, forty-five".
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