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130326306512159 is a prime number
BaseRepresentation
bin11101101000011111110101…
…001101000101110100011111
3122002110001222101021121002002
4131220133311031011310133
5114040231233431342114
61141103024554552515
736310523240250632
oct3550376515056437
9562401871247062
10130326306512159
113858709247646a
121274a14043873b
1357949444c5404
142427b80dc1c19
1510101464a47de
hex7687f5345d1f

130326306512159 has 2 divisors, whose sum is σ = 130326306512160. Its totient is φ = 130326306512158.

The previous prime is 130326306512111. The next prime is 130326306512167. The reversal of 130326306512159 is 951215603623031.

It is a strong prime.

It is an emirp because it is prime and its reverse (951215603623031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130326306512159 is a prime.

It is a super-2 number, since 2×1303263065121592 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130326306512459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65163153256079 + 65163153256080.

It is an arithmetic number, because the mean of its divisors is an integer number (65163153256080).

Almost surely, 2130326306512159 is an apocalyptic number.

130326306512159 is a deficient number, since it is larger than the sum of its proper divisors (1).

130326306512159 is an equidigital number, since it uses as much as digits as its factorization.

130326306512159 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 874800, while the sum is 47.

The spelling of 130326306512159 in words is "one hundred thirty trillion, three hundred twenty-six billion, three hundred six million, five hundred twelve thousand, one hundred fifty-nine".