Base | Representation |
---|---|
bin | 10010111101110010110… |
… | …110100101011001110011 |
3 | 11121121001100122112211022 |
4 | 102331302312211121303 |
5 | 132323130303033131 |
6 | 2434421221010055 |
7 | 163106016143252 |
oct | 22756266453163 |
9 | 4547040575738 |
10 | 1303302002291 |
11 | 462800004403 |
12 | 19070925392b |
13 | 95b9322ac53 |
14 | 47119d26799 |
15 | 23d7dc7137b |
hex | 12f72da5673 |
1303302002291 has 2 divisors, whose sum is σ = 1303302002292. Its totient is φ = 1303302002290.
The previous prime is 1303302002273. The next prime is 1303302002293. The reversal of 1303302002291 is 1922002033031.
It is a strong prime.
It is an emirp because it is prime and its reverse (1922002033031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1303302002291 - 214 = 1303301985907 is a prime.
It is a super-2 number, since 2×13033020022912 (a number of 25 digits) contains 22 as substring.
Together with 1303302002293, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1303302002291.
It is not a weakly prime, because it can be changed into another prime (1303302002293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651651001145 + 651651001146.
It is an arithmetic number, because the mean of its divisors is an integer number (651651001146).
Almost surely, 21303302002291 is an apocalyptic number.
1303302002291 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303302002291 is an equidigital number, since it uses as much as digits as its factorization.
1303302002291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 26.
The spelling of 1303302002291 in words is "one trillion, three hundred three billion, three hundred two million, two thousand, two hundred ninety-one".
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