Base | Representation |
---|---|
bin | 10010111101110010111… |
… | …111011101111110011011 |
3 | 11121121001112000212102211 |
4 | 102331302333131332123 |
5 | 132323131402044123 |
6 | 2434421342535551 |
7 | 163106045013052 |
oct | 22756277357633 |
9 | 4547045025384 |
10 | 1303304331163 |
11 | 46280135509a |
12 | 190709b975b7 |
13 | 95b93864c93 |
14 | 4711a371399 |
15 | 23d7e08140d |
hex | 12f72fddf9b |
1303304331163 has 2 divisors, whose sum is σ = 1303304331164. Its totient is φ = 1303304331162.
The previous prime is 1303304331079. The next prime is 1303304331211. The reversal of 1303304331163 is 3611334033031.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (3611334033031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1303304331163 is a prime.
It is not a weakly prime, because it can be changed into another prime (1303304332163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651652165581 + 651652165582.
It is an arithmetic number, because the mean of its divisors is an integer number (651652165582).
Almost surely, 21303304331163 is an apocalyptic number.
1303304331163 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303304331163 is an equidigital number, since it uses as much as digits as its factorization.
1303304331163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17496, while the sum is 31.
Adding to 1303304331163 its reverse (3611334033031), we get a palindrome (4914638364194).
The spelling of 1303304331163 in words is "one trillion, three hundred three billion, three hundred four million, three hundred thirty-one thousand, one hundred sixty-three".
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