Base | Representation |
---|---|
bin | 1011110110101000000101… |
… | …0110110000010101100011 |
3 | 1201010221201012212122210121 |
4 | 2331222001112300111203 |
5 | 3202013242324031313 |
6 | 43415153545541111 |
7 | 2513416251440551 |
oct | 275520126602543 |
9 | 51127635778717 |
10 | 13033101002083 |
11 | 417534181a568 |
12 | 1565a9b1a4797 |
13 | 737029639696 |
14 | 330b3c248bd1 |
15 | 17904a65628d |
hex | bda815b0563 |
13033101002083 has 2 divisors, whose sum is σ = 13033101002084. Its totient is φ = 13033101002082.
The previous prime is 13033101002069. The next prime is 13033101002113. The reversal of 13033101002083 is 38020010133031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13033101002083 - 237 = 12895662048611 is a prime.
It is not a weakly prime, because it can be changed into another prime (13033101002003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516550501041 + 6516550501042.
It is an arithmetic number, because the mean of its divisors is an integer number (6516550501042).
Almost surely, 213033101002083 is an apocalyptic number.
13033101002083 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033101002083 is an equidigital number, since it uses as much as digits as its factorization.
13033101002083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
The spelling of 13033101002083 in words is "thirteen trillion, thirty-three billion, one hundred one million, two thousand, eighty-three".
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