Base | Representation |
---|---|
bin | 1011110110101000000101… |
… | …0110110000010100010011 |
3 | 1201010221201012212122200122 |
4 | 2331222001112300110103 |
5 | 3202013242324031003 |
6 | 43415153545540455 |
7 | 2513416251440405 |
oct | 275520126602423 |
9 | 51127635778618 |
10 | 13033101002003 |
11 | 417534181a4a5 |
12 | 1565a9b1a472b |
13 | 737029639634 |
14 | 330b3c248b75 |
15 | 17904a656238 |
hex | bda815b0513 |
13033101002003 has 2 divisors, whose sum is σ = 13033101002004. Its totient is φ = 13033101002002.
The previous prime is 13033101001981. The next prime is 13033101002011. The reversal of 13033101002003 is 30020010133031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13033101002003 - 28 = 13033101001747 is a prime.
It is a super-2 number, since 2×130331010020032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13033101002083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516550501001 + 6516550501002.
It is an arithmetic number, because the mean of its divisors is an integer number (6516550501002).
Almost surely, 213033101002003 is an apocalyptic number.
13033101002003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033101002003 is an equidigital number, since it uses as much as digits as its factorization.
13033101002003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 13033101002003 its reverse (30020010133031), we get a palindrome (43053111135034).
The spelling of 13033101002003 in words is "thirteen trillion, thirty-three billion, one hundred one million, two thousand, three".
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