130331116052437 has 2 divisors, whose sum is σ = 130331116052438. Its totient is φ = 130331116052436.

The previous prime is 130331116052419. The next prime is 130331116052461. The reversal of 130331116052437 is 734250611133031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109368948277521 + 20962167774916 = 10457961^2 + 4578446^2 .

It is an emirp because it is prime and its reverse (734250611133031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130331116052437 - 2¹¹ = 130331116050389 is a prime.

It is a super-2 number, since 2×130331116052437² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130331116052437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130331176052437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65165558026218 + 65165558026219.

It is an arithmetic number, because the mean of its divisors is an integer number (65165558026219).

Almost surely, 2^{130331116052437} is an apocalyptic number.

It is an amenable number.

130331116052437 is a deficient number, since it is larger than the sum of its proper divisors (1).

130331116052437 is an equidigital number, since it uses as much as digits as its factorization.

130331116052437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 136080, while the sum is 40.

Adding to 130331116052437 its reverse (734250611133031), we get a palindrome (864581727185468).

The spelling of 130331116052437 in words is "one hundred thirty trillion, three hundred thirty-one billion, one hundred sixteen million, fifty-two thousand, four hundred thirty-seven".