Base | Representation |
---|---|
bin | 10010111101110011011… |
… | …101001110101110100111 |
3 | 11121121002001201020120220 |
4 | 102331303131032232213 |
5 | 132323140401224111 |
6 | 2434422222055423 |
7 | 163106201226036 |
oct | 22756335165647 |
9 | 4547061636526 |
10 | 1303312133031 |
11 | 4628057a3817 |
12 | 19071071a573 |
13 | 95b9536717c |
14 | 4711b40271d |
15 | 23d7eac2e06 |
hex | 12f7374eba7 |
1303312133031 has 4 divisors (see below), whose sum is σ = 1737749510712. Its totient is φ = 868874755352.
The previous prime is 1303312133017. The next prime is 1303312133077.
1303312133031 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1303312133031 - 215 = 1303312100263 is a prime.
It is a super-2 number, since 2×13033121330312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1303312132992 and 1303312133010.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1303312033031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217218688836 + ... + 217218688841.
It is an arithmetic number, because the mean of its divisors is an integer number (434437377678).
Almost surely, 21303312133031 is an apocalyptic number.
1303312133031 is a deficient number, since it is larger than the sum of its proper divisors (434437377681).
1303312133031 is an equidigital number, since it uses as much as digits as its factorization.
1303312133031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 434437377680.
The product of its (nonzero) digits is 1458, while the sum is 24.
The spelling of 1303312133031 in words is "one trillion, three hundred three billion, three hundred twelve million, one hundred thirty-three thousand, thirty-one".
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