Base | Representation |
---|---|
bin | 1011110110101000001100… |
… | …0101011010110111001011 |
3 | 1201010221210020110112001221 |
4 | 2331222003011122313023 |
5 | 3202013322240341412 |
6 | 43415200503422511 |
7 | 2513420053144102 |
oct | 275520305326713 |
9 | 51127706415057 |
10 | 13033130012107 |
11 | 4175357134197 |
12 | 1565aa8a54a37 |
13 | 737032655b8a |
14 | 330b4203b039 |
15 | 17904ce86b07 |
hex | bda8315adcb |
13033130012107 has 2 divisors, whose sum is σ = 13033130012108. Its totient is φ = 13033130012106.
The previous prime is 13033130012083. The next prime is 13033130012131. The reversal of 13033130012107 is 70121003133031.
It is a balanced prime because it is at equal distance from previous prime (13033130012083) and next prime (13033130012131).
It is a cyclic number.
It is not a de Polignac number, because 13033130012107 - 211 = 13033130010059 is a prime.
It is not a weakly prime, because it can be changed into another prime (13033130012197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516565006053 + 6516565006054.
It is an arithmetic number, because the mean of its divisors is an integer number (6516565006054).
Almost surely, 213033130012107 is an apocalyptic number.
13033130012107 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033130012107 is an equidigital number, since it uses as much as digits as its factorization.
13033130012107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 13033130012107 its reverse (70121003133031), we get a palindrome (83154133145138).
The spelling of 13033130012107 in words is "thirteen trillion, thirty-three billion, one hundred thirty million, twelve thousand, one hundred seven".
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