Base | Representation |
---|---|
bin | 1011110110101000001110… |
… | …1111010101100011010011 |
3 | 1201010221211000010210011212 |
4 | 2331222003233111203103 |
5 | 3202013333044003103 |
6 | 43415201535130335 |
7 | 2513420245430666 |
oct | 275520357254323 |
9 | 51127730123155 |
10 | 13033141000403 |
11 | 4175362359927 |
12 | 1565ab06739ab |
13 | 737034a02524 |
14 | 330b4369b6dd |
15 | 17904de077d8 |
hex | bda83bd58d3 |
13033141000403 has 8 divisors (see below), whose sum is σ = 13310713152000. Its totient is φ = 12755580152200.
The previous prime is 13033141000391. The next prime is 13033141000421. The reversal of 13033141000403 is 30400014133031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13033141000403 - 24 = 13033141000387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13033141000433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 474623 + ... + 5127528.
It is an arithmetic number, because the mean of its divisors is an integer number (1663839144000).
Almost surely, 213033141000403 is an apocalyptic number.
13033141000403 is a deficient number, since it is larger than the sum of its proper divisors (277572151597).
13033141000403 is an equidigital number, since it uses as much as digits as its factorization.
13033141000403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5651697.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 13033141000403 its reverse (30400014133031), we get a palindrome (43433155133434).
The spelling of 13033141000403 in words is "thirteen trillion, thirty-three billion, one hundred forty-one million, four hundred three", and thus it is an aban number.
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