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13033141000403 = 47494995602151
BaseRepresentation
bin1011110110101000001110…
…1111010101100011010011
31201010221211000010210011212
42331222003233111203103
53202013333044003103
643415201535130335
72513420245430666
oct275520357254323
951127730123155
1013033141000403
114175362359927
121565ab06739ab
13737034a02524
14330b4369b6dd
1517904de077d8
hexbda83bd58d3

13033141000403 has 8 divisors (see below), whose sum is σ = 13310713152000. Its totient is φ = 12755580152200.

The previous prime is 13033141000391. The next prime is 13033141000421. The reversal of 13033141000403 is 30400014133031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13033141000403 - 24 = 13033141000387 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13033141000433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 474623 + ... + 5127528.

It is an arithmetic number, because the mean of its divisors is an integer number (1663839144000).

Almost surely, 213033141000403 is an apocalyptic number.

13033141000403 is a deficient number, since it is larger than the sum of its proper divisors (277572151597).

13033141000403 is an equidigital number, since it uses as much as digits as its factorization.

13033141000403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5651697.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13033141000403 its reverse (30400014133031), we get a palindrome (43433155133434).

The spelling of 13033141000403 in words is "thirteen trillion, thirty-three billion, one hundred forty-one million, four hundred three", and thus it is an aban number.

Divisors: 1 47 49499 2326453 5602151 263301097 277300872349 13033141000403