Base | Representation |
---|---|
bin | 1011110110101000011101… |
… | …0101000100010110111111 |
3 | 1201010221222012110102012020 |
4 | 2331222013111010112333 |
5 | 3202013444003114403 |
6 | 43415211530011223 |
7 | 2513421606343245 |
oct | 275520725042677 |
9 | 51127865412166 |
10 | 13033201223103 |
11 | 4175393352056 |
12 | 1565b08876b13 |
13 | 737044329969 |
14 | 330b4b696795 |
15 | 179054351453 |
hex | bda875445bf |
13033201223103 has 4 divisors (see below), whose sum is σ = 17377601630808. Its totient is φ = 8688800815400.
The previous prime is 13033201223087. The next prime is 13033201223113. The reversal of 13033201223103 is 30132210233031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13033201223103 - 24 = 13033201223087 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13033201223113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2172200203848 + ... + 2172200203853.
It is an arithmetic number, because the mean of its divisors is an integer number (4344400407702).
Almost surely, 213033201223103 is an apocalyptic number.
13033201223103 is a deficient number, since it is larger than the sum of its proper divisors (4344400407705).
13033201223103 is an equidigital number, since it uses as much as digits as its factorization.
13033201223103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4344400407704.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 13033201223103 its reverse (30132210233031), we get a palindrome (43165411456134).
The spelling of 13033201223103 in words is "thirteen trillion, thirty-three billion, two hundred one million, two hundred twenty-three thousand, one hundred three".
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