Base | Representation |
---|---|
bin | 1011110110101000110111… |
… | …1011110001000111110101 |
3 | 1201010222020220222001100121 |
4 | 2331222031323301013311 |
5 | 3202014210334444341 |
6 | 43415230525011541 |
7 | 2513424423242056 |
oct | 275521573610765 |
9 | 51128226861317 |
10 | 13033312031221 |
11 | 417543a955909 |
12 | 1565b399b3bb1 |
13 | 737061285ab1 |
14 | 330b5c29c72d |
15 | 17905de3d4d1 |
hex | bda8def11f5 |
13033312031221 has 2 divisors, whose sum is σ = 13033312031222. Its totient is φ = 13033312031220.
The previous prime is 13033312031213. The next prime is 13033312031297. The reversal of 13033312031221 is 12213021333031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8114032008196 + 4919280023025 = 2848514^2 + 2217945^2 .
It is a cyclic number.
It is not a de Polignac number, because 13033312031221 - 23 = 13033312031213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13033312031021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516656015610 + 6516656015611.
It is an arithmetic number, because the mean of its divisors is an integer number (6516656015611).
Almost surely, 213033312031221 is an apocalyptic number.
It is an amenable number.
13033312031221 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033312031221 is an equidigital number, since it uses as much as digits as its factorization.
13033312031221 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13033312031221 its reverse (12213021333031), we get a palindrome (25246333364252).
The spelling of 13033312031221 in words is "thirteen trillion, thirty-three billion, three hundred twelve million, thirty-one thousand, two hundred twenty-one".
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