Base | Representation |
---|---|
bin | 11000010001101101… |
… | …01001001100100101 |
3 | 1020122022201120012002 |
4 | 30020312221030211 |
5 | 203143030203013 |
6 | 5553143535045 |
7 | 640660306253 |
oct | 141066511445 |
9 | 36568646162 |
10 | 13033444133 |
11 | 5589048536 |
12 | 2638a5a485 |
13 | 12c92b1528 |
14 | 8b8d935d3 |
15 | 51435b358 |
hex | 308da9325 |
13033444133 has 2 divisors, whose sum is σ = 13033444134. Its totient is φ = 13033444132.
The previous prime is 13033444097. The next prime is 13033444141. The reversal of 13033444133 is 33144433031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11837875204 + 1195568929 = 108802^2 + 34577^2 .
It is a cyclic number.
It is not a de Polignac number, because 13033444133 - 212 = 13033440037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13033444096 and 13033444105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13033444733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516722066 + 6516722067.
It is an arithmetic number, because the mean of its divisors is an integer number (6516722067).
Almost surely, 213033444133 is an apocalyptic number.
It is an amenable number.
13033444133 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033444133 is an equidigital number, since it uses as much as digits as its factorization.
13033444133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 13033444133 its reverse (33144433031), we get a palindrome (46177877164).
The spelling of 13033444133 in words is "thirteen billion, thirty-three million, four hundred forty-four thousand, one hundred thirty-three".
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