1303350340453 has 4 divisors (see below), whose sum is σ = 1489543246240. Its totient is φ = 1117157434668.

The previous prime is 1303350340451. The next prime is 1303350340489. The reversal of 1303350340453 is 3540430533031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1303350340453 - 2¹ = 1303350340451 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1303350340451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93096452883 + ... + 93096452896.

It is an arithmetic number, because the mean of its divisors is an integer number (372385811560).

Almost surely, 2^{1303350340453} is an apocalyptic number.

It is an amenable number.

1303350340453 is a deficient number, since it is larger than the sum of its proper divisors (186192905787).

1303350340453 is an equidigital number, since it uses as much as digits as its factorization.

1303350340453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 186192905786.

The product of its (nonzero) digits is 97200, while the sum is 34.

Adding to 1303350340453 its reverse (3540430533031), we get a palindrome (4843780873484).

The spelling of 1303350340453 in words is "one trillion, three hundred three billion, three hundred fifty million, three hundred forty thousand, four hundred fifty-three".