1303400101125 has 32 divisors (see below), whose sum is σ = 2169473859072. Its totient is φ = 694949256000.

The previous prime is 1303400101121. The next prime is 1303400101127. The reversal of 1303400101125 is 5211010043031.

It is not a de Polignac number, because 1303400101125 - 2² = 1303400101121 is a prime.

It is a super-3 number, since 3×1303400101125³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1303400101121) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 832980 + ... + 1816770.

It is an arithmetic number, because the mean of its divisors is an integer number (67796058096).

Almost surely, 2^{1303400101125} is an apocalyptic number.

1303400101125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1303400101125 is a deficient number, since it is larger than the sum of its proper divisors (866073757947).

1303400101125 is an equidigital number, since it uses as much as digits as its factorization.

1303400101125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 987342 (or 987332 counting only the distinct ones).

The product of its (nonzero) digits is 360, while the sum is 21.

Adding to 1303400101125 its reverse (5211010043031), we get a palindrome (6514410144156).

The spelling of 1303400101125 in words is "one trillion, three hundred three billion, four hundred million, one hundred one thousand, one hundred twenty-five".