Base | Representation |
---|---|
bin | 11000010001110010… |
… | …01100000101101101 |
3 | 1020122100222110102111 |
4 | 30020321030011231 |
5 | 203143213030331 |
6 | 5553210124021 |
7 | 640666055416 |
oct | 141071140555 |
9 | 36570873374 |
10 | 13034111341 |
11 | 5589463849 |
12 | 2639120611 |
13 | 12c9486124 |
14 | 8b90c880d |
15 | 51443ddb1 |
hex | 308e4c16d |
13034111341 has 4 divisors (see below), whose sum is σ = 13034972412. Its totient is φ = 13033250272.
The previous prime is 13034111333. The next prime is 13034111351. The reversal of 13034111341 is 14311143031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 11170376100 + 1863735241 = 105690^2 + 43171^2 .
It is a cyclic number.
It is not a de Polignac number, because 13034111341 - 23 = 13034111333 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13034111351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 407416 + ... + 438241.
It is an arithmetic number, because the mean of its divisors is an integer number (3258743103).
Almost surely, 213034111341 is an apocalyptic number.
It is an amenable number.
13034111341 is a deficient number, since it is larger than the sum of its proper divisors (861071).
13034111341 is an equidigital number, since it uses as much as digits as its factorization.
13034111341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 861070.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 13034111341 its reverse (14311143031), we get a palindrome (27345254372).
The spelling of 13034111341 in words is "thirteen billion, thirty-four million, one hundred eleven thousand, three hundred forty-one".
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