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1303411325101 is a prime number
BaseRepresentation
bin10010111101111001010…
…111100111100010101101
311121121022222100201112021
4102331321113213202231
5132323341244400401
62434440124110141
7163111514314534
oct22757127474255
94547288321467
101303411325101
11462856793236
12190739995351
1395baca86cc2
144712a66331b
1523d886682a1
hex12f795e78ad

1303411325101 has 2 divisors, whose sum is σ = 1303411325102. Its totient is φ = 1303411325100.

The previous prime is 1303411325087. The next prime is 1303411325113. The reversal of 1303411325101 is 1015231143031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1231820295876 + 71591029225 = 1109874^2 + 267565^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1303411325101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1303411323101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651705662550 + 651705662551.

It is an arithmetic number, because the mean of its divisors is an integer number (651705662551).

Almost surely, 21303411325101 is an apocalyptic number.

It is an amenable number.

1303411325101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303411325101 is an equidigital number, since it uses as much as digits as its factorization.

1303411325101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 1303411325101 its reverse (1015231143031), we get a palindrome (2318642468132).

The spelling of 1303411325101 in words is "one trillion, three hundred three billion, four hundred eleven million, three hundred twenty-five thousand, one hundred one".