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1303433220054 = 23731034124287
BaseRepresentation
bin10010111101111010101…
…011001000111111010110
311121121101111120002202110
4102331322223020333112
5132323412401020204
62434442225251450
7163112201365320
oct22757253107726
94547344502673
101303433220054
11462868088239
12190745193b86
1395bb4481ab4
144712d522610
1523d8a540889
hex12f7aac8fd6

1303433220054 has 16 divisors (see below), whose sum is σ = 2979275931648. Its totient is φ = 372409491432.

The previous prime is 1303433220043. The next prime is 1303433220059. The reversal of 1303433220054 is 4500223343031.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1303433220059) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15517062102 + ... + 15517062185.

It is an arithmetic number, because the mean of its divisors is an integer number (186204745728).

Almost surely, 21303433220054 is an apocalyptic number.

1303433220054 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

1303433220054 is an abundant number, since it is smaller than the sum of its proper divisors (1675842711594).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1303433220054 is a wasteful number, since it uses less digits than its factorization.

1303433220054 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31034124299.

The product of its (nonzero) digits is 25920, while the sum is 30.

Adding to 1303433220054 its reverse (4500223343031), we get a palindrome (5803656563085).

The spelling of 1303433220054 in words is "one trillion, three hundred three billion, four hundred thirty-three million, two hundred twenty thousand, fifty-four".

Divisors: 1 2 3 6 7 14 21 42 31034124287 62068248574 93102372861 186204745722 217238870009 434477740018 651716610027 1303433220054