Base | Representation |
---|---|
bin | 111100101100101011… |
… | …0001100110000001101 |
3 | 110110110011210000021221 |
4 | 1321121112030300031 |
5 | 4113423042314014 |
6 | 135514150123341 |
7 | 12263100544153 |
oct | 1713126146015 |
9 | 413404700257 |
10 | 130348010509 |
11 | 5030a065622 |
12 | 21319350551 |
13 | c3a4012302 |
14 | 64477b93d3 |
15 | 35cd6a7b24 |
hex | 1e5958cc0d |
130348010509 has 2 divisors, whose sum is σ = 130348010510. Its totient is φ = 130348010508.
The previous prime is 130348010501. The next prime is 130348010537. The reversal of 130348010509 is 905010843031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 129114455625 + 1233554884 = 359325^2 + 35122^2 .
It is a cyclic number.
It is not a de Polignac number, because 130348010509 - 23 = 130348010501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130348010501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65174005254 + 65174005255.
It is an arithmetic number, because the mean of its divisors is an integer number (65174005255).
Almost surely, 2130348010509 is an apocalyptic number.
It is an amenable number.
130348010509 is a deficient number, since it is larger than the sum of its proper divisors (1).
130348010509 is an equidigital number, since it uses as much as digits as its factorization.
130348010509 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 34.
The spelling of 130348010509 in words is "one hundred thirty billion, three hundred forty-eight million, ten thousand, five hundred nine".
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