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1303506290969 is a prime number
BaseRepresentation
bin10010111101111111000…
…001111000100100011001
311121121120121001111012122
4102331333001320210121
5132324040102302334
62434453355351025
7163114046442131
oct22757701704431
94547517044178
101303506290969
114628a5356523
12190765752475
1395bc665731c
1447139103ac1
1523d91b7632e
hex12f7f078919

1303506290969 has 2 divisors, whose sum is σ = 1303506290970. Its totient is φ = 1303506290968.

The previous prime is 1303506290887. The next prime is 1303506290971. The reversal of 1303506290969 is 9690926053031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1303506290944 + 25 = 1141712^2 + 5^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1303506290969 is a prime.

It is a super-2 number, since 2×13035062909692 (a number of 25 digits) contains 22 as substring.

Together with 1303506290971, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1303506290969.

It is not a weakly prime, because it can be changed into another prime (1303506296969) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651753145484 + 651753145485.

It is an arithmetic number, because the mean of its divisors is an integer number (651753145485).

Almost surely, 21303506290969 is an apocalyptic number.

It is an amenable number.

1303506290969 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303506290969 is an equidigital number, since it uses as much as digits as its factorization.

1303506290969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2361960, while the sum is 53.

The spelling of 1303506290969 in words is "one trillion, three hundred three billion, five hundred six million, two hundred ninety thousand, nine hundred sixty-nine".