130351158740343 has 8 divisors (see below), whose sum is σ = 177499450199808. Its totient is φ = 85051819887224.

The previous prime is 130351158740311. The next prime is 130351158740381. The reversal of 130351158740343 is 343047851153031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130351158740343 - 2⁵ = 130351158740311 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130351158740292 and 130351158740301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130351158740443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 462238151421 + ... + 462238151702.

It is an arithmetic number, because the mean of its divisors is an integer number (22187431274976).

Almost surely, 2^{130351158740343} is an apocalyptic number.

130351158740343 is a deficient number, since it is larger than the sum of its proper divisors (47148291459465).

130351158740343 is an equidigital number, since it uses as much as digits as its factorization.

130351158740343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 924476303173.

The product of its (nonzero) digits is 1814400, while the sum is 48.

The spelling of 130351158740343 in words is "one hundred thirty trillion, three hundred fifty-one billion, one hundred fifty-eight million, seven hundred forty thousand, three hundred forty-three".