Base | Representation |
---|---|
bin | 1011110110110000000100… |
… | …1011100000000001100011 |
3 | 1201011011020200012020100221 |
4 | 2331230001023200001203 |
5 | 3202032140324112311 |
6 | 43420150434423511 |
7 | 2513523351613225 |
oct | 275540113400143 |
9 | 51134220166327 |
10 | 13035245535331 |
11 | 4176242305098 |
12 | 1566399431b97 |
13 | 7372aba1a576 |
14 | 330ca2da8415 |
15 | 179123a68671 |
hex | bdb012e0063 |
13035245535331 has 4 divisors (see below), whose sum is σ = 13084809206832. Its totient is φ = 12985681863832.
The previous prime is 13035245535293. The next prime is 13035245535343. The reversal of 13035245535331 is 13353554253031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13035245535331 - 239 = 12485489721443 is a prime.
It is a super-2 number, since 2×130352455353312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13035285535331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24781835356 + ... + 24781835881.
It is an arithmetic number, because the mean of its divisors is an integer number (3271202301708).
Almost surely, 213035245535331 is an apocalyptic number.
13035245535331 is a deficient number, since it is larger than the sum of its proper divisors (49563671501).
13035245535331 is an equidigital number, since it uses as much as digits as its factorization.
13035245535331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49563671500.
The product of its (nonzero) digits is 1215000, while the sum is 43.
Adding to 13035245535331 its reverse (13353554253031), we get a palindrome (26388799788362).
The spelling of 13035245535331 in words is "thirteen trillion, thirty-five billion, two hundred forty-five million, five hundred thirty-five thousand, three hundred thirty-one".
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