Base | Representation |
---|---|
bin | 10010111110000001101… |
… | …000110100011100100100 |
3 | 11121121200122101210020110 |
4 | 102332001220310130210 |
5 | 132324132303132012 |
6 | 2434502001333020 |
7 | 163115120423526 |
oct | 22760150643444 |
9 | 4547618353213 |
10 | 1303550052132 |
11 | 462918025979 |
12 | 190778337170 |
13 | 95c02739ac3 |
14 | 47140c55a16 |
15 | 23d9591c73c |
hex | 12f81a34724 |
1303550052132 has 24 divisors (see below), whose sum is σ = 3062030328000. Its totient is φ = 431600464096.
The previous prime is 1303550052121. The next prime is 1303550052163. The reversal of 1303550052132 is 2312500553031.
It is a super-3 number, since 3×13035500521323 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1303550052132.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 364525632 + ... + 364529207.
It is an arithmetic number, because the mean of its divisors is an integer number (127584597000).
Almost surely, 21303550052132 is an apocalyptic number.
1303550052132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1303550052132 is an abundant number, since it is smaller than the sum of its proper divisors (1758480275868).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1303550052132 is a wasteful number, since it uses less digits than its factorization.
1303550052132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 729054995 (or 729054993 counting only the distinct ones).
The product of its (nonzero) digits is 13500, while the sum is 30.
The spelling of 1303550052132 in words is "one trillion, three hundred three billion, five hundred fifty million, fifty-two thousand, one hundred thirty-two".
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