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130355032013 is a prime number
BaseRepresentation
bin111100101100111000…
…0111110111111001101
3110110110122222201222122
41321121300332333031
54113431342011023
6135515000422325
712263214330053
oct1713160767715
9413418881878
10130355032013
1150313020a18
122131b7779a5
13c3a560024b
1464486c61d3
1535ce0e32c8
hex1e59c3efcd

130355032013 has 2 divisors, whose sum is σ = 130355032014. Its totient is φ = 130355032012.

The previous prime is 130355031997. The next prime is 130355032033. The reversal of 130355032013 is 310230553031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119160968809 + 11194063204 = 345197^2 + 105802^2 .

It is a cyclic number.

It is not a de Polignac number, because 130355032013 - 24 = 130355031997 is a prime.

It is a super-2 number, since 2×1303550320132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130355032033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65177516006 + 65177516007.

It is an arithmetic number, because the mean of its divisors is an integer number (65177516007).

Almost surely, 2130355032013 is an apocalyptic number.

It is an amenable number.

130355032013 is a deficient number, since it is larger than the sum of its proper divisors (1).

130355032013 is an equidigital number, since it uses as much as digits as its factorization.

130355032013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4050, while the sum is 26.

Adding to 130355032013 its reverse (310230553031), we get a palindrome (440585585044).

The spelling of 130355032013 in words is "one hundred thirty billion, three hundred fifty-five million, thirty-two thousand, thirteen".