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13035513187841 is a prime number
BaseRepresentation
bin1011110110110001000100…
…1000100000111000000001
31201011011221022211101120212
42331230101020200320001
53202033212334002331
643420233155243505
72513533111616234
oct275542110407001
951134838741525
1013035513187841
11417636a3a5411
121566452ba9595
13737322300a31
14330cca75b41b
1517913c2d7d2b
hexbdb11220e01

13035513187841 has 2 divisors, whose sum is σ = 13035513187842. Its totient is φ = 13035513187840.

The previous prime is 13035513187799. The next prime is 13035513187861. The reversal of 13035513187841 is 14878131553031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7085157945616 + 5950355242225 = 2661796^2 + 2439335^2 .

It is a cyclic number.

It is not a de Polignac number, because 13035513187841 - 26 = 13035513187777 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13035513187841.

It is not a weakly prime, because it can be changed into another prime (13035513187861) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6517756593920 + 6517756593921.

It is an arithmetic number, because the mean of its divisors is an integer number (6517756593921).

Almost surely, 213035513187841 is an apocalyptic number.

It is an amenable number.

13035513187841 is a deficient number, since it is larger than the sum of its proper divisors (1).

13035513187841 is an equidigital number, since it uses as much as digits as its factorization.

13035513187841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1209600, while the sum is 50.

The spelling of 13035513187841 in words is "thirteen trillion, thirty-five billion, five hundred thirteen million, one hundred eighty-seven thousand, eight hundred forty-one".