1303794821345 has 4 divisors (see below), whose sum is σ = 1564553785620. Its totient is φ = 1043035857072.

The previous prime is 1303794821239. The next prime is 1303794821411. The reversal of 1303794821345 is 5431284973031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 877626091489 + 426168729856 = 936817^2 + 652816^2 .

It is a cyclic number.

It is not a de Polignac number, because 1303794821345 - 2¹² = 1303794817249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1303794821293 and 1303794821302.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130379482130 + ... + 130379482139.

It is an arithmetic number, because the mean of its divisors is an integer number (391138446405).

Almost surely, 2^{1303794821345} is an apocalyptic number.

It is an amenable number.

1303794821345 is a deficient number, since it is larger than the sum of its proper divisors (260758964275).

1303794821345 is an equidigital number, since it uses as much as digits as its factorization.

1303794821345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 260758964274.

The product of its (nonzero) digits is 2177280, while the sum is 50.

The spelling of 1303794821345 in words is "one trillion, three hundred three billion, seven hundred ninety-four million, eight hundred twenty-one thousand, three hundred forty-five".