Base | Representation |
---|---|
bin | 111100101101110000… |
… | …1100100000001010111 |
3 | 110110112201112002120221 |
4 | 1321123201210001113 |
5 | 4114011420400311 |
6 | 135521533135211 |
7 | 12264023223253 |
oct | 1713341440127 |
9 | 413481462527 |
10 | 130384543831 |
11 | 50328748653 |
12 | 2132962a507 |
13 | c3ab763c69 |
14 | 644c5a9263 |
15 | 35d19c2671 |
hex | 1e5b864057 |
130384543831 has 2 divisors, whose sum is σ = 130384543832. Its totient is φ = 130384543830.
The previous prime is 130384543699. The next prime is 130384543871. The reversal of 130384543831 is 138345483031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130384543831 - 223 = 130376155223 is a prime.
It is a super-2 number, since 2×1303845438312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130384543871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65192271915 + 65192271916.
It is an arithmetic number, because the mean of its divisors is an integer number (65192271916).
Almost surely, 2130384543831 is an apocalyptic number.
130384543831 is a deficient number, since it is larger than the sum of its proper divisors (1).
130384543831 is an equidigital number, since it uses as much as digits as its factorization.
130384543831 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 43.
The spelling of 130384543831 in words is "one hundred thirty billion, three hundred eighty-four million, five hundred forty-three thousand, eight hundred thirty-one".
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