Base | Representation |
---|---|
bin | 10010111110011011111… |
… | …001100011000010110111 |
3 | 11121122211100110012220211 |
4 | 102332123321203002313 |
5 | 132331033101114134 |
6 | 2435013421010251 |
7 | 163132050412564 |
oct | 22763371430267 |
9 | 4548740405824 |
10 | 1303990644919 |
11 | 4630237a6846 |
12 | 19087b9b3987 |
13 | 95c72ac19b1 |
14 | 4718358586b |
15 | 23dbe44d764 |
hex | 12f9be630b7 |
1303990644919 has 2 divisors, whose sum is σ = 1303990644920. Its totient is φ = 1303990644918.
The previous prime is 1303990644907. The next prime is 1303990644997. The reversal of 1303990644919 is 9194460993031.
It is a weak prime.
It is an emirp because it is prime and its reverse (9194460993031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1303990644919 - 215 = 1303990612151 is a prime.
It is a super-2 number, since 2×13039906449192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1303990624919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651995322459 + 651995322460.
It is an arithmetic number, because the mean of its divisors is an integer number (651995322460).
Almost surely, 21303990644919 is an apocalyptic number.
1303990644919 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303990644919 is an equidigital number, since it uses as much as digits as its factorization.
1303990644919 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5668704, while the sum is 58.
The spelling of 1303990644919 in words is "one trillion, three hundred three billion, nine hundred ninety million, six hundred forty-four thousand, nine hundred nineteen".
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