1304001334033 has 2 divisors, whose sum is σ = 1304001334034. Its totient is φ = 1304001334032.

The previous prime is 1304001334007. The next prime is 1304001334043. The reversal of 1304001334033 is 3304331004031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1303186631184 + 814702849 = 1141572^2 + 28543^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304001334033 - 2⁵ = 1304001334001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1304001333989 and 1304001334007.

It is not a weakly prime, because it can be changed into another prime (1304001334043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652000667016 + 652000667017.

It is an arithmetic number, because the mean of its divisors is an integer number (652000667017).

Almost surely, 2^{1304001334033} is an apocalyptic number.

It is an amenable number.

1304001334033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304001334033 is an equidigital number, since it uses as much as digits as its factorization.

1304001334033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 1304001334033 its reverse (3304331004031), we get a palindrome (4608332338064).

The spelling of 1304001334033 in words is "one trillion, three hundred four billion, one million, three hundred thirty-four thousand, thirty-three".