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1304010453115 = 51171222717413
BaseRepresentation
bin10010111110011101000…
…101000111000001111011
311121122212201201120122201
4102332131011013001323
5132331103133444430
62435015405331031
7163132410652456
oct22763505070173
94548781646581
101304010453115
114630339a5a57
12190886566a77
1395c76c38a16
144718606049d
1523dc10628ca
hex12f9d14707b

1304010453115 has 8 divisors (see below), whose sum is σ = 1566148855248. Its totient is φ = 1042317488160.

The previous prime is 1304010453103. The next prime is 1304010453143. The reversal of 1304010453115 is 5113540104031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1304010453115 - 221 = 1304008355963 is a prime.

It is a super-2 number, since 2×13040104531152 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 111352852 + ... + 111364561.

It is an arithmetic number, because the mean of its divisors is an integer number (195768606906).

Almost surely, 21304010453115 is an apocalyptic number.

1304010453115 is a deficient number, since it is larger than the sum of its proper divisors (262138402133).

1304010453115 is a wasteful number, since it uses less digits than its factorization.

1304010453115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 222718589.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 1304010453115 its reverse (5113540104031), we get a palindrome (6417550557146).

The spelling of 1304010453115 in words is "one trillion, three hundred four billion, ten million, four hundred fifty-three thousand, one hundred fifteen".

Divisors: 1 5 1171 5855 222717413 1113587065 260802090623 1304010453115