Base | Representation |
---|---|
bin | 1011110111000010010001… |
… | …1100010100011111110111 |
3 | 1201011121212020011011200202 |
4 | 2331300210130110133313 |
5 | 3202122142310130143 |
6 | 43422315355031115 |
7 | 2514055426060421 |
oct | 275604434243767 |
9 | 51147766134622 |
10 | 13040132114423 |
11 | 417831a694307 |
12 | 1567321a3b49b |
13 | 7378aa21699b |
14 | 331207d83811 |
15 | 17930ca68ab8 |
hex | bdc247147f7 |
13040132114423 has 2 divisors, whose sum is σ = 13040132114424. Its totient is φ = 13040132114422.
The previous prime is 13040132114417. The next prime is 13040132114437. The reversal of 13040132114423 is 32441123104031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13040132114423 - 210 = 13040132113399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13040132114623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520066057211 + 6520066057212.
It is an arithmetic number, because the mean of its divisors is an integer number (6520066057212).
Almost surely, 213040132114423 is an apocalyptic number.
13040132114423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13040132114423 is an equidigital number, since it uses as much as digits as its factorization.
13040132114423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 13040132114423 its reverse (32441123104031), we get a palindrome (45481255218454).
The spelling of 13040132114423 in words is "thirteen trillion, forty billion, one hundred thirty-two million, one hundred fourteen thousand, four hundred twenty-three".
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