13040133023 has 2 divisors, whose sum is σ = 13040133024. Its totient is φ = 13040133022.

The previous prime is 13040132993. The next prime is 13040133037. The reversal of 13040133023 is 32033104031.

It is a strong prime.

It is an emirp because it is prime and its reverse (32033104031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13040133023 - 2⁸ = 13040132767 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13040132986 and 13040133004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13040133083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520066511 + 6520066512.

It is an arithmetic number, because the mean of its divisors is an integer number (6520066512).

Almost surely, 2^13040133023 is an apocalyptic number.

13040133023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13040133023 is an equidigital number, since it uses as much as digits as its factorization.

13040133023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 20.

Adding to 13040133023 its reverse (32033104031), we get a palindrome (45073237054).

The spelling of 13040133023 in words is "thirteen billion, forty million, one hundred thirty-three thousand, twenty-three".