Base | Representation |
---|---|
bin | 111100101110010001… |
… | …0010000110100001011 |
3 | 110110120220102210021201 |
4 | 1321130202100310023 |
5 | 4114030241121043 |
6 | 135523340445031 |
7 | 12264320333323 |
oct | 1713442206413 |
9 | 413526383251 |
10 | 130401504523 |
11 | 50337282454 |
12 | 21333249777 |
13 | c3b2121b84 |
14 | 6450942283 |
15 | 35d3222c4d |
hex | 1e5c890d0b |
130401504523 has 4 divisors (see below), whose sum is σ = 130456366600. Its totient is φ = 130346642448.
The previous prime is 130401504451. The next prime is 130401504601. The reversal of 130401504523 is 325405104031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130401504523 - 221 = 130399407371 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130401504491 and 130401504500.
It is not an unprimeable number, because it can be changed into a prime (130401504923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27427473 + ... + 27432226.
It is an arithmetic number, because the mean of its divisors is an integer number (32614091650).
Almost surely, 2130401504523 is an apocalyptic number.
130401504523 is a deficient number, since it is larger than the sum of its proper divisors (54862077).
130401504523 is an equidigital number, since it uses as much as digits as its factorization.
130401504523 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54862076.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 130401504523 its reverse (325405104031), we get a palindrome (455806608554).
The spelling of 130401504523 in words is "one hundred thirty billion, four hundred one million, five hundred four thousand, five hundred twenty-three".
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