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1304016283 is a prime number
BaseRepresentation
bin100110110111001…
…1011010110011011
310100212201220001101
41031232123112123
510132312010113
6333221332231
744212645513
oct11556332633
93325656041
101304016283
1160a0a0809
12304867077
1317a21308b
14c5288843
15797352dd
hex4db9b59b

1304016283 has 2 divisors, whose sum is σ = 1304016284. Its totient is φ = 1304016282.

The previous prime is 1304016281. The next prime is 1304016319. The reversal of 1304016283 is 3826104031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1304016283 - 21 = 1304016281 is a prime.

Together with 1304016281, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1304016281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652008141 + 652008142.

It is an arithmetic number, because the mean of its divisors is an integer number (652008142).

Almost surely, 21304016283 is an apocalyptic number.

1304016283 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304016283 is an equidigital number, since it uses as much as digits as its factorization.

1304016283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

The square root of 1304016283 is about 36111.1656278221. The cubic root of 1304016283 is about 1092.5156616194.

It can be divided in two parts, 1304016 and 283, that multiplied together give a triangular number (369036528 = T27167).

The spelling of 1304016283 in words is "one billion, three hundred four million, sixteen thousand, two hundred eighty-three".