130402100011 has 8 divisors (see below), whose sum is σ = 133471555184. Its totient is φ = 127334319840.

The previous prime is 130402099981. The next prime is 130402100047. The reversal of 130402100011 is 110001204031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130402100011 - 2¹¹ = 130402097963 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130402099964 and 130402100000.

It is not an unprimeable number, because it can be changed into a prime (130402100111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 260520 + ... + 573301.

It is an arithmetic number, because the mean of its divisors is an integer number (16683944398).

Almost surely, 2^130402100011 is an apocalyptic number.

130402100011 is a deficient number, since it is larger than the sum of its proper divisors (3069455173).

130402100011 is an equidigital number, since it uses as much as digits as its factorization.

130402100011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 837501.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 130402100011 its reverse (110001204031), we get a palindrome (240403304042).

The spelling of 130402100011 in words is "one hundred thirty billion, four hundred two million, one hundred thousand, eleven".