Base | Representation |
---|---|
bin | 1011110111000010101110… |
… | …1110111011001110010001 |
3 | 1201011122011202022120001202 |
4 | 2331300223232323032101 |
5 | 3202122420113312040 |
6 | 43422335444440545 |
7 | 2514061442544023 |
oct | 275605356731621 |
9 | 51148152276052 |
10 | 13040254432145 |
11 | 4178382739436 |
12 | 15673569a9155 |
13 | 7378c9672835 |
14 | 33121a304013 |
15 | 17931867b015 |
hex | bdc2bbbb391 |
13040254432145 has 8 divisors (see below), whose sum is σ = 15648352644480. Its totient is φ = 10432171995120.
The previous prime is 13040254432063. The next prime is 13040254432199. The reversal of 13040254432145 is 54123445204031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13040254432145 - 28 = 13040254431889 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13040254432099 and 13040254432108.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2041865 + ... + 5499974.
It is an arithmetic number, because the mean of its divisors is an integer number (1956044080560).
Almost surely, 213040254432145 is an apocalyptic number.
It is an amenable number.
13040254432145 is a deficient number, since it is larger than the sum of its proper divisors (2608098212335).
13040254432145 is an equidigital number, since it uses as much as digits as its factorization.
13040254432145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7887655.
The product of its (nonzero) digits is 230400, while the sum is 38.
Adding to 13040254432145 its reverse (54123445204031), we get a palindrome (67163699636176).
The spelling of 13040254432145 in words is "thirteen trillion, forty billion, two hundred fifty-four million, four hundred thirty-two thousand, one hundred forty-five".
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