Base | Representation |
---|---|
bin | 111100101110010100… |
… | …0000001000110001001 |
3 | 110110121000021102112021 |
4 | 1321130220001012021 |
5 | 4114031132404001 |
6 | 135523433044441 |
7 | 12264336215242 |
oct | 1713450010611 |
9 | 413530242467 |
10 | 130403013001 |
11 | 50338112828 |
12 | 21333856721 |
13 | c3b252c671 |
14 | 6450c15cc9 |
15 | 35d341eba1 |
hex | 1e5ca01189 |
130403013001 has 2 divisors, whose sum is σ = 130403013002. Its totient is φ = 130403013000.
The previous prime is 130403012983. The next prime is 130403013019. The reversal of 130403013001 is 100310304031.
It is a balanced prime because it is at equal distance from previous prime (130403012983) and next prime (130403013019).
It can be written as a sum of positive squares in only one way, i.e., 97169358400 + 33233654601 = 311720^2 + 182301^2 .
It is a cyclic number.
It is not a de Polignac number, because 130403013001 - 25 = 130403012969 is a prime.
It is not a weakly prime, because it can be changed into another prime (130403713001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65201506500 + 65201506501.
It is an arithmetic number, because the mean of its divisors is an integer number (65201506501).
Almost surely, 2130403013001 is an apocalyptic number.
It is an amenable number.
130403013001 is a deficient number, since it is larger than the sum of its proper divisors (1).
130403013001 is an equidigital number, since it uses as much as digits as its factorization.
130403013001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 130403013001 its reverse (100310304031), we get a palindrome (230713317032).
The spelling of 130403013001 in words is "one hundred thirty billion, four hundred three million, thirteen thousand, one".
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