Search a number
-
+
13040313114 = 2317457279751
BaseRepresentation
bin11000010010100001…
…10110001100011010
31020122210122112122210
430021100312030122
5203201310004424
65553551055550
7641102555403
oct141120661432
936583575583
1013040313114
115591a0a284
12263b2115b6
1312ca847c0a
148b9c609aa
15514c66729
hex30943631a

13040313114 has 32 divisors (see below), whose sum is σ = 27675305856. Its totient is φ = 4082112000.

The previous prime is 13040313109. The next prime is 13040313119. The reversal of 13040313114 is 41131304031.

It is an interprime number because it is at equal distance from previous prime (13040313109) and next prime (13040313119).

It is a super-2 number, since 2×130403131142 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13040313119) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 93262 + ... + 186489.

It is an arithmetic number, because the mean of its divisors is an integer number (864853308).

Almost surely, 213040313114 is an apocalyptic number.

13040313114 is an abundant number, since it is smaller than the sum of its proper divisors (14634992742).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13040313114 is a wasteful number, since it uses less digits than its factorization.

13040313114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 280230.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13040313114 its reverse (41131304031), we get a palindrome (54171617145).

The spelling of 13040313114 in words is "thirteen billion, forty million, three hundred thirteen thousand, one hundred fourteen".

Divisors: 1 2 3 6 17 34 51 102 457 914 1371 2742 7769 15538 23307 46614 279751 559502 839253 1678506 4755767 9511534 14267301 28534602 127846207 255692414 383538621 767077242 2173385519 4346771038 6520156557 13040313114