Base | Representation |
---|---|
bin | 111100101110010100… |
… | …0111001011111001101 |
3 | 110110121000201011101002 |
4 | 1321130220321133031 |
5 | 4114031212301411 |
6 | 135523442030045 |
7 | 12264341166533 |
oct | 1713450713715 |
9 | 413530634332 |
10 | 130403243981 |
11 | 5033826031a |
12 | 21333948325 |
13 | c3b25b083a |
14 | 6450c76153 |
15 | 35d346833b |
hex | 1e5ca397cd |
130403243981 has 2 divisors, whose sum is σ = 130403243982. Its totient is φ = 130403243980.
The previous prime is 130403243977. The next prime is 130403244001. The reversal of 130403243981 is 189342304031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 108132457225 + 22270786756 = 328835^2 + 149234^2 .
It is a cyclic number.
It is not a de Polignac number, because 130403243981 - 22 = 130403243977 is a prime.
It is a super-2 number, since 2×1304032439812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130403243921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65201621990 + 65201621991.
It is an arithmetic number, because the mean of its divisors is an integer number (65201621991).
Almost surely, 2130403243981 is an apocalyptic number.
It is an amenable number.
130403243981 is a deficient number, since it is larger than the sum of its proper divisors (1).
130403243981 is an equidigital number, since it uses as much as digits as its factorization.
130403243981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 38.
The spelling of 130403243981 in words is "one hundred thirty billion, four hundred three million, two hundred forty-three thousand, nine hundred eighty-one".
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