Base | Representation |
---|---|
bin | 111100101110010100… |
… | …0111001011111111111 |
3 | 110110121000201011102221 |
4 | 1321130220321133333 |
5 | 4114031212302111 |
6 | 135523442030211 |
7 | 12264341166634 |
oct | 1713450713777 |
9 | 413530634387 |
10 | 130403244031 |
11 | 50338260365 |
12 | 21333948367 |
13 | c3b25b0878 |
14 | 6450c7618b |
15 | 35d3468371 |
hex | 1e5ca397ff |
130403244031 has 2 divisors, whose sum is σ = 130403244032. Its totient is φ = 130403244030.
The previous prime is 130403244001. The next prime is 130403244043. The reversal of 130403244031 is 130442304031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130403244031 - 27 = 130403243903 is a prime.
It is a super-2 number, since 2×1304032440312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130403243987 and 130403244005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130403244001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65201622015 + 65201622016.
It is an arithmetic number, because the mean of its divisors is an integer number (65201622016).
Almost surely, 2130403244031 is an apocalyptic number.
130403244031 is a deficient number, since it is larger than the sum of its proper divisors (1).
130403244031 is an equidigital number, since it uses as much as digits as its factorization.
130403244031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 130403244031 its reverse (130442304031), we get a palindrome (260845548062).
The spelling of 130403244031 in words is "one hundred thirty billion, four hundred three million, two hundred forty-four thousand, thirty-one".
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