130404103331 has 4 divisors (see below), whose sum is σ = 130469340000. Its totient is φ = 130338866664.

The previous prime is 130404103309. The next prime is 130404103439. The reversal of 130404103331 is 133301404031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130404103331 - 2¹⁴ = 130404086947 is a prime.

It is a super-2 number, since 2×130404103331² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130404103297 and 130404103306.

It is not an unprimeable number, because it can be changed into a prime (130404103231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32615336 + ... + 32619333.

It is an arithmetic number, because the mean of its divisors is an integer number (32617335000).

Almost surely, 2^130404103331 is an apocalyptic number.

130404103331 is a deficient number, since it is larger than the sum of its proper divisors (65236669).

130404103331 is an equidigital number, since it uses as much as digits as its factorization.

130404103331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65236668.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 130404103331 its reverse (133301404031), we get a palindrome (263705507362).

The spelling of 130404103331 in words is "one hundred thirty billion, four hundred four million, one hundred three thousand, three hundred thirty-one".