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1304043214321 is a prime number
BaseRepresentation
bin10010111110011111000…
…010000101010111110001
311121122222000101000120201
4102332133002011113301
5132331140030324241
62435022535435201
7163133256301261
oct22763702052761
94548860330521
101304043214321
11463050441a31
12190895525b01
1395c80969753
144718a54b7a1
1523dc3d84931
hex12f9f0855f1

1304043214321 has 2 divisors, whose sum is σ = 1304043214322. Its totient is φ = 1304043214320.

The previous prime is 1304043214291. The next prime is 1304043214343. The reversal of 1304043214321 is 1234123404031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1274390374321 + 29652840000 = 1128889^2 + 172200^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304043214321 - 235 = 1269683475953 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1304043214321.

It is not a weakly prime, because it can be changed into another prime (1304043214351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652021607160 + 652021607161.

It is an arithmetic number, because the mean of its divisors is an integer number (652021607161).

Almost surely, 21304043214321 is an apocalyptic number.

It is an amenable number.

1304043214321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304043214321 is an equidigital number, since it uses as much as digits as its factorization.

1304043214321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1304043214321 its reverse (1234123404031), we get a palindrome (2538166618352).

The spelling of 1304043214321 in words is "one trillion, three hundred four billion, forty-three million, two hundred fourteen thousand, three hundred twenty-one".