13040512125133 has 8 divisors (see below), whose sum is σ = 13091884744320. Its totient is φ = 12989237267040.

The previous prime is 13040512125031. The next prime is 13040512125139. The reversal of 13040512125133 is 33152121504031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13040512125133 - 2¹⁷ = 13040511994061 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13040512125095 and 13040512125104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13040512125139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24172960 + ... + 24706537.

It is an arithmetic number, because the mean of its divisors is an integer number (1636485593040).

Almost surely, 2^{13040512125133} is an apocalyptic number.

It is an amenable number.

13040512125133 is a deficient number, since it is larger than the sum of its proper divisors (51372619187).

13040512125133 is an equidigital number, since it uses as much as digits as its factorization.

13040512125133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48880547.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 13040512125133 its reverse (33152121504031), we get a palindrome (46192633629164).

The spelling of 13040512125133 in words is "thirteen trillion, forty billion, five hundred twelve million, one hundred twenty-five thousand, one hundred thirty-three".