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1304054111315 = 52200311853421
BaseRepresentation
bin10010111110011111101…
…011101001110001010011
311121122222202212122110002
4102332133223221301103
5132331200323030230
62435024005200215
7163133451025034
oct22763753516123
94548882778402
101304054111315
1146305660500a
1219089910006b
1395c82cb3687
144718bb86a8b
1523dc4cd8545
hex12f9fae9c53

1304054111315 has 8 divisors (see below), whose sum is σ = 1564936186128. Its totient is φ = 1043195787360.

The previous prime is 1304054111303. The next prime is 1304054111323. The reversal of 1304054111315 is 5131114504031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1304054111315 - 24 = 1304054111299 is a prime.

It is a super-2 number, since 2×13040541113152 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5816696 + ... + 6036725.

It is an arithmetic number, because the mean of its divisors is an integer number (195617023266).

Almost surely, 21304054111315 is an apocalyptic number.

1304054111315 is a deficient number, since it is larger than the sum of its proper divisors (260882074813).

1304054111315 is a wasteful number, since it uses less digits than its factorization.

1304054111315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11875429.

The product of its (nonzero) digits is 3600, while the sum is 29.

Adding to 1304054111315 its reverse (5131114504031), we get a palindrome (6435168615346).

The spelling of 1304054111315 in words is "one trillion, three hundred four billion, fifty-four million, one hundred eleven thousand, three hundred fifteen".

Divisors: 1 5 22003 110015 11853421 59267105 260810822263 1304054111315