13041012111 has 4 divisors (see below), whose sum is σ = 17388016152. Its totient is φ = 8694008072.

The previous prime is 13041012091. The next prime is 13041012139. The reversal of 13041012111 is 11121014031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11121014031 = 3 ⋅3707004677.

It is a cyclic number.

It is not a de Polignac number, because 13041012111 - 2¹⁷ = 13040881039 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13041012151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2173502016 + ... + 2173502021.

It is an arithmetic number, because the mean of its divisors is an integer number (4347004038).

Almost surely, 2^13041012111 is an apocalyptic number.

13041012111 is a deficient number, since it is larger than the sum of its proper divisors (4347004041).

13041012111 is an equidigital number, since it uses as much as digits as its factorization.

13041012111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4347004040.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 13041012111 its reverse (11121014031), we get a palindrome (24162026142).

The spelling of 13041012111 in words is "thirteen billion, forty-one million, twelve thousand, one hundred eleven".